(10/2^8)x-5=-0.3

Solution for (10/2^8)x-5=-0.3 equation:

(10/2^8)x-5=-0.3

We move all terms to the left:

(10/2^8)x-5-(-0.3)=0


Domain of the equation: 2^8)x!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

(10/2^8)x-4.7=0

We multiply parentheses

10x^2-4.7=0

a = 10; b = 0; c = -4.7;
Δ = b2-4ac
Δ = 02-4·10·(-4.7)
Δ = 188
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{188}=\sqrt{4*47}=\sqrt{4}*\sqrt{47}=2\sqrt{47}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{47}}{2*10}=\frac{0-2\sqrt{47}}{20}
=-\frac{2\sqrt{47}}{20}
=-\frac{\sqrt{47}}{10}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{47}}{2*10}=\frac{0+2\sqrt{47}}{20}
=\frac{2\sqrt{47}}{20}
=\frac{\sqrt{47}}{10}
$